# Solve 3sinx

Hint khổng lồ another possible way: 3 sin x -2= cos x Rightarrow 3 sin x -2=sqrt1-sin^2 x squaring you have a second degree equation in sin x. Also in this case be careful lớn extraneous ...

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How vày you solve displaystylesinx=-cosx in the interval displaystyle0lexle2pi ?
displaystylex=frac3pi4ordisplaystylefrac7pi4 Explanation:Asdisplaystylesinx=-cosx , we have displaystylesinx+cosx=0 ...
First of all, thanks for the A2A since this brings back memories from 14 years ago when I was trying to lớn learn Statics and vectors on my own. Looking at the expression I recognize I can write it as Rsin(x-a)=Rsin xcos a-Rcos xsin a ...
displaystylex=fracpi4+npi Explanation:We have: displaystylesinx-cosx=0 Which we can rearrange as follows: displaystyle hereforesinx=cosx ...
frac1sqrt2sinx-frac1sqrt2cosx=frac1sqrt2 or sinleft(x-45^circ ight)=sin45^circ, which gives x-45^circ=45^circ+360^circk, where k is an integer ...
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left< eginarray l l 2 và 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 và 0 và 3 \ -1 & 1 và 5 endarray ight>

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